Binary search tree with minimum potential












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How to construct a n-node binary serach tree such that its potential is the minimum? The size, rank and potential are defined as follows



The size $s(v)$ is the number of nodes in a subtree (include v) with the root $v$.



The rank $r(v) = log_2(s(v))$.



The potential of a tree $Phi(T) = sum_{v in T} r(v)$.



We are trying to minimize $Phi(T)$ with $n$ given nodes. I think the answer is a binary search tree. And through calculation I caluclate the potential is $leq 2n$. But I don't know how to prove this is indeed the minimum.










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    How to construct a n-node binary serach tree such that its potential is the minimum? The size, rank and potential are defined as follows



    The size $s(v)$ is the number of nodes in a subtree (include v) with the root $v$.



    The rank $r(v) = log_2(s(v))$.



    The potential of a tree $Phi(T) = sum_{v in T} r(v)$.



    We are trying to minimize $Phi(T)$ with $n$ given nodes. I think the answer is a binary search tree. And through calculation I caluclate the potential is $leq 2n$. But I don't know how to prove this is indeed the minimum.










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      How to construct a n-node binary serach tree such that its potential is the minimum? The size, rank and potential are defined as follows



      The size $s(v)$ is the number of nodes in a subtree (include v) with the root $v$.



      The rank $r(v) = log_2(s(v))$.



      The potential of a tree $Phi(T) = sum_{v in T} r(v)$.



      We are trying to minimize $Phi(T)$ with $n$ given nodes. I think the answer is a binary search tree. And through calculation I caluclate the potential is $leq 2n$. But I don't know how to prove this is indeed the minimum.










      share|cite|improve this question













      How to construct a n-node binary serach tree such that its potential is the minimum? The size, rank and potential are defined as follows



      The size $s(v)$ is the number of nodes in a subtree (include v) with the root $v$.



      The rank $r(v) = log_2(s(v))$.



      The potential of a tree $Phi(T) = sum_{v in T} r(v)$.



      We are trying to minimize $Phi(T)$ with $n$ given nodes. I think the answer is a binary search tree. And through calculation I caluclate the potential is $leq 2n$. But I don't know how to prove this is indeed the minimum.







      trees






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      asked Nov 25 at 7:44









      Lawerance

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