Uniqueness of solution based on characteristic curves
up vote
2
down vote
favorite
I have a pde
$$begin{cases} u_t − xu_x = 2u & xinmathbb{R}, t>0\
u(x, 0) = frac{1}{1+x^2}
end{cases}$$
I've solved it using method of characteristics ($u=frac{1}{1+x^2e^{2t}}e^{2t})$ and plotted charactersitic curves.
Consider the upper half-space since $t>0$.
How to argue using the drawing whether or not it is the unique solution? Thank you.
pde
add a comment |
up vote
2
down vote
favorite
I have a pde
$$begin{cases} u_t − xu_x = 2u & xinmathbb{R}, t>0\
u(x, 0) = frac{1}{1+x^2}
end{cases}$$
I've solved it using method of characteristics ($u=frac{1}{1+x^2e^{2t}}e^{2t})$ and plotted charactersitic curves.
Consider the upper half-space since $t>0$.
How to argue using the drawing whether or not it is the unique solution? Thank you.
pde
Are you plotting in the $(t, u)$ plane? $(x, u)$? $(t, x)$?
– Mattos
Nov 19 at 1:46
@Mattos This is the projection on the $(x,t)$-plane
– dxdydz
Nov 19 at 2:01
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have a pde
$$begin{cases} u_t − xu_x = 2u & xinmathbb{R}, t>0\
u(x, 0) = frac{1}{1+x^2}
end{cases}$$
I've solved it using method of characteristics ($u=frac{1}{1+x^2e^{2t}}e^{2t})$ and plotted charactersitic curves.
Consider the upper half-space since $t>0$.
How to argue using the drawing whether or not it is the unique solution? Thank you.
pde
I have a pde
$$begin{cases} u_t − xu_x = 2u & xinmathbb{R}, t>0\
u(x, 0) = frac{1}{1+x^2}
end{cases}$$
I've solved it using method of characteristics ($u=frac{1}{1+x^2e^{2t}}e^{2t})$ and plotted charactersitic curves.
Consider the upper half-space since $t>0$.
How to argue using the drawing whether or not it is the unique solution? Thank you.
pde
pde
asked Nov 18 at 22:38
dxdydz
1169
1169
Are you plotting in the $(t, u)$ plane? $(x, u)$? $(t, x)$?
– Mattos
Nov 19 at 1:46
@Mattos This is the projection on the $(x,t)$-plane
– dxdydz
Nov 19 at 2:01
add a comment |
Are you plotting in the $(t, u)$ plane? $(x, u)$? $(t, x)$?
– Mattos
Nov 19 at 1:46
@Mattos This is the projection on the $(x,t)$-plane
– dxdydz
Nov 19 at 2:01
Are you plotting in the $(t, u)$ plane? $(x, u)$? $(t, x)$?
– Mattos
Nov 19 at 1:46
Are you plotting in the $(t, u)$ plane? $(x, u)$? $(t, x)$?
– Mattos
Nov 19 at 1:46
@Mattos This is the projection on the $(x,t)$-plane
– dxdydz
Nov 19 at 2:01
@Mattos This is the projection on the $(x,t)$-plane
– dxdydz
Nov 19 at 2:01
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3004237%2funiqueness-of-solution-based-on-characteristic-curves%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Are you plotting in the $(t, u)$ plane? $(x, u)$? $(t, x)$?
– Mattos
Nov 19 at 1:46
@Mattos This is the projection on the $(x,t)$-plane
– dxdydz
Nov 19 at 2:01