How do you find the values of a and b that makes the function continuous?











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How do you find the values of $a$ and $b$ that makes the function continuous?



$f(x) = a x^2 - 1$ for $x<1$, $2$ for $x=1$, $2/bx$ for $x>1$.










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    How do you find the values of $a$ and $b$ that makes the function continuous?



    $f(x) = a x^2 - 1$ for $x<1$, $2$ for $x=1$, $2/bx$ for $x>1$.










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      How do you find the values of $a$ and $b$ that makes the function continuous?



      $f(x) = a x^2 - 1$ for $x<1$, $2$ for $x=1$, $2/bx$ for $x>1$.










      share|cite|improve this question















      How do you find the values of $a$ and $b$ that makes the function continuous?



      $f(x) = a x^2 - 1$ for $x<1$, $2$ for $x=1$, $2/bx$ for $x>1$.







      calculus






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      edited Nov 19 at 0:43









      David G. Stork

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      9,30321232










      asked Nov 19 at 0:37









      Mit34

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          Hint: Take the limit from the left and from the right and make them equal






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          • Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
            – Andreas Blass
            Nov 19 at 0:42










          • @AndreasBlass, You are right
            – gb2017
            Nov 19 at 0:44











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          1 Answer
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          active

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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

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          up vote
          1
          down vote













          Hint: Take the limit from the left and from the right and make them equal






          share|cite|improve this answer





















          • Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
            – Andreas Blass
            Nov 19 at 0:42










          • @AndreasBlass, You are right
            – gb2017
            Nov 19 at 0:44















          up vote
          1
          down vote













          Hint: Take the limit from the left and from the right and make them equal






          share|cite|improve this answer





















          • Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
            – Andreas Blass
            Nov 19 at 0:42










          • @AndreasBlass, You are right
            – gb2017
            Nov 19 at 0:44













          up vote
          1
          down vote










          up vote
          1
          down vote









          Hint: Take the limit from the left and from the right and make them equal






          share|cite|improve this answer












          Hint: Take the limit from the left and from the right and make them equal







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 19 at 0:41









          gb2017

          944




          944












          • Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
            – Andreas Blass
            Nov 19 at 0:42










          • @AndreasBlass, You are right
            – gb2017
            Nov 19 at 0:44


















          • Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
            – Andreas Blass
            Nov 19 at 0:42










          • @AndreasBlass, You are right
            – gb2017
            Nov 19 at 0:44
















          Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
          – Andreas Blass
          Nov 19 at 0:42




          Here "make them equal" means make them equal to each other and to the value of the function at the point in question.
          – Andreas Blass
          Nov 19 at 0:42












          @AndreasBlass, You are right
          – gb2017
          Nov 19 at 0:44




          @AndreasBlass, You are right
          – gb2017
          Nov 19 at 0:44


















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