Riemann zeta zeros Fourier like divergent square wave. Can you complete this analogy?
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The question is to complete this analogy:
$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$
is to:
$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$
as:
$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$
is to what?
$f(t) = text{?} tag{4}$
I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:
$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$
where:
$$g(t)=frac{partial vartheta (t)}{partial t}$$
and where $vartheta(t)$ is the Riemann-Siegel theta function,
has a nice plot:
The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.
$Z(t)$ is the Riemann-Siegel zeta function.
number-theory fourier-analysis analytic-number-theory riemann-zeta
add a comment |
up vote
1
down vote
favorite
The question is to complete this analogy:
$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$
is to:
$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$
as:
$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$
is to what?
$f(t) = text{?} tag{4}$
I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:
$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$
where:
$$g(t)=frac{partial vartheta (t)}{partial t}$$
and where $vartheta(t)$ is the Riemann-Siegel theta function,
has a nice plot:
The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.
$Z(t)$ is the Riemann-Siegel zeta function.
number-theory fourier-analysis analytic-number-theory riemann-zeta
$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49
What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56
$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
The question is to complete this analogy:
$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$
is to:
$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$
as:
$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$
is to what?
$f(t) = text{?} tag{4}$
I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:
$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$
where:
$$g(t)=frac{partial vartheta (t)}{partial t}$$
and where $vartheta(t)$ is the Riemann-Siegel theta function,
has a nice plot:
The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.
$Z(t)$ is the Riemann-Siegel zeta function.
number-theory fourier-analysis analytic-number-theory riemann-zeta
The question is to complete this analogy:
$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$
is to:
$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$
as:
$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$
is to what?
$f(t) = text{?} tag{4}$
I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:
$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$
where:
$$g(t)=frac{partial vartheta (t)}{partial t}$$
and where $vartheta(t)$ is the Riemann-Siegel theta function,
has a nice plot:
The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.
$Z(t)$ is the Riemann-Siegel zeta function.
number-theory fourier-analysis analytic-number-theory riemann-zeta
number-theory fourier-analysis analytic-number-theory riemann-zeta
edited Nov 17 at 10:13
asked Nov 17 at 10:08
Mats Granvik
3,34632249
3,34632249
$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49
What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56
$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36
add a comment |
$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49
What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56
$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36
$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49
$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49
What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56
What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56
$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36
$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36
add a comment |
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$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49
What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56
$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36