Riemann zeta zeros Fourier like divergent square wave. Can you complete this analogy?











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The question is to complete this analogy:




$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$



is to:



$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$



as:



$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$



is to what?
$f(t) = text{?} tag{4}$




I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:



$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$



where:



$$g(t)=frac{partial vartheta (t)}{partial t}$$



and where $vartheta(t)$ is the Riemann-Siegel theta function,



has a nice plot:



Riemann zeta zeros square wave passing through the zeta zeros



The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.



$Z(t)$ is the Riemann-Siegel zeta function.










share|cite|improve this question
























  • $P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
    – reuns
    Nov 17 at 10:49












  • What $f_{vartheta}(t)$ means to you
    – reuns
    Nov 17 at 10:56










  • $f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
    – Mats Granvik
    Nov 17 at 11:36















up vote
1
down vote

favorite












The question is to complete this analogy:




$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$



is to:



$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$



as:



$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$



is to what?
$f(t) = text{?} tag{4}$




I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:



$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$



where:



$$g(t)=frac{partial vartheta (t)}{partial t}$$



and where $vartheta(t)$ is the Riemann-Siegel theta function,



has a nice plot:



Riemann zeta zeros square wave passing through the zeta zeros



The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.



$Z(t)$ is the Riemann-Siegel zeta function.










share|cite|improve this question
























  • $P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
    – reuns
    Nov 17 at 10:49












  • What $f_{vartheta}(t)$ means to you
    – reuns
    Nov 17 at 10:56










  • $f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
    – Mats Granvik
    Nov 17 at 11:36













up vote
1
down vote

favorite









up vote
1
down vote

favorite











The question is to complete this analogy:




$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$



is to:



$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$



as:



$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$



is to what?
$f(t) = text{?} tag{4}$




I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:



$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$



where:



$$g(t)=frac{partial vartheta (t)}{partial t}$$



and where $vartheta(t)$ is the Riemann-Siegel theta function,



has a nice plot:



Riemann zeta zeros square wave passing through the zeta zeros



The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.



$Z(t)$ is the Riemann-Siegel zeta function.










share|cite|improve this question















The question is to complete this analogy:




$$left|Z(t)right|=left|zeta left(frac{1}{2}+i tright)right| tag{1}$$



is to:



$$Z(t)=e^{i vartheta (t)} zeta left(frac{1}{2}+i tright) tag{2}$$



as:



$$left|f(t)right|=left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i t-1)}}right| tag{3}$$



is to what?
$f(t) = text{?} tag{4}$




I am asking this because $f(t)$ divided by Riemann Siegel theta and the $k$-th Harmonic number:



$$f_{vartheta(t)}(t)=frac{text{sgn}
(Z(t))left|sumlimits_{n=1}^{n=k} frac{1}{n} zeta(1/2+i cdot t)sumlimits_{d|n}frac{mu(d)}{d^{(1/2+i cdot t-1)}}right|}{g(t)+H_{text{k}}}$$



where:



$$g(t)=frac{partial vartheta (t)}{partial t}$$



and where $vartheta(t)$ is the Riemann-Siegel theta function,



has a nice plot:



Riemann zeta zeros square wave passing through the zeta zeros



The blue graph passes through the Riemann zeta zeros, like the Riemann-Siegel zeta function. However, the square wave $f(t)$ is divergent despite the appearance of the plot.



$Z(t)$ is the Riemann-Siegel zeta function.







number-theory fourier-analysis analytic-number-theory riemann-zeta






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share|cite|improve this question













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edited Nov 17 at 10:13

























asked Nov 17 at 10:08









Mats Granvik

3,34632249




3,34632249












  • $P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
    – reuns
    Nov 17 at 10:49












  • What $f_{vartheta}(t)$ means to you
    – reuns
    Nov 17 at 10:56










  • $f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
    – Mats Granvik
    Nov 17 at 11:36


















  • $P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
    – reuns
    Nov 17 at 10:49












  • What $f_{vartheta}(t)$ means to you
    – reuns
    Nov 17 at 10:56










  • $f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
    – Mats Granvik
    Nov 17 at 11:36
















$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49






$P_k(s)=sum_{n=1}^k n^{-1} sum_{d |n} mu(d) d^{1-s}$ is a Dirichlet polynomial with real coefficients so $P_k(s) e^{-i h_k(s)/2}$ is real for $Re(s) = 1/2$ where $h_k(s) = log P_k(s) -log P_k(1-s)$ is analytic on $Re(s) = 1/2$.
– reuns
Nov 17 at 10:49














What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56




What $f_{vartheta}(t)$ means to you
– reuns
Nov 17 at 10:56












$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36




$f_{vartheta}(t)$ means that the function is divided by Riemann Siegelt theta.
– Mats Granvik
Nov 17 at 11:36















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