What is the pmf of an exponential distribution? [closed]
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I've been able to find the PDF and CDF but I cannot find the pmf of an exponential distribution anywhere.
probability
asked Dec 15 '18 at 4:22
UserUser
31
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closed as off-topic by Brahadeesh, amWhy, Lord Shark the Unknown, Saad, Batominovski Dec 15 '18 at 5:40
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$begingroup$
I've been able to find the PDF and CDF but I cannot find the pmf of an exponential distribution anywhere.
probability
asked Dec 15 '18 at 4:22
UserUser
31
$endgroup$
closed as off-topic by Brahadeesh, amWhy, Lord Shark the Unknown, Saad, Batominovski Dec 15 '18 at 5:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, amWhy, Saad, Batominovski
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
I've been able to find the PDF and CDF but I cannot find the pmf of an exponential distribution anywhere.
probability
asked Dec 15 '18 at 4:22
UserUser
31
$endgroup$
I've been able to find the PDF and CDF but I cannot find the pmf of an exponential distribution anywhere.
probability
probability
asked Dec 15 '18 at 4:22
UserUser
31
asked Dec 15 '18 at 4:22
UserUser
31
asked Dec 15 '18 at 4:22
UserUser
31
asked Dec 15 '18 at 4:22
UserUser
31
asked Dec 15 '18 at 4:22
UserUser
31
31
closed as off-topic by Brahadeesh, amWhy, Lord Shark the Unknown, Saad, Batominovski Dec 15 '18 at 5:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, amWhy, Saad, Batominovski
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Brahadeesh, amWhy, Lord Shark the Unknown, Saad, Batominovski Dec 15 '18 at 5:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, amWhy, Saad, Batominovski
If this question can be reworded to fit the rules in the help center, please edit the question.
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1 Answer
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votes
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That's because it doesn't have one. A probability mass function $p(x) = Pr(X=x)$ only makes sense for discrete random variables X. For continuous random variables, you integrate the density to get a probability; for discrete random variables, you sum the point masses to get the probability for an event.
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
That's because it doesn't have one. A probability mass function $p(x) = Pr(X=x)$ only makes sense for discrete random variables X. For continuous random variables, you integrate the density to get a probability; for discrete random variables, you sum the point masses to get the probability for an event.
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
$endgroup$
add a comment |
$begingroup$
That's because it doesn't have one. A probability mass function $p(x) = Pr(X=x)$ only makes sense for discrete random variables X. For continuous random variables, you integrate the density to get a probability; for discrete random variables, you sum the point masses to get the probability for an event.
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
$endgroup$
add a comment |
$begingroup$
That's because it doesn't have one. A probability mass function $p(x) = Pr(X=x)$ only makes sense for discrete random variables X. For continuous random variables, you integrate the density to get a probability; for discrete random variables, you sum the point masses to get the probability for an event.
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
$endgroup$
That's because it doesn't have one. A probability mass function $p(x) = Pr(X=x)$ only makes sense for discrete random variables X. For continuous random variables, you integrate the density to get a probability; for discrete random variables, you sum the point masses to get the probability for an event.
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
answered Dec 15 '18 at 4:30
MatthiasMatthias
2287
2287
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