What does “constant rate” mean in universal composable commitment scheme?












3














I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?










share|improve this question






















  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21
















3














I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?










share|improve this question






















  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21














3












3








3







I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?










share|improve this question













I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?







commitments






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 18 '18 at 17:14









CryptoLover

402212




402212












  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21


















  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21
















Can you please post a reference to a paper or something where you encountered this term?
– SEJPM
Dec 18 '18 at 17:21




Can you please post a reference to a paper or something where you encountered this term?
– SEJPM
Dec 18 '18 at 17:21










1 Answer
1






active

oldest

votes


















4














Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






share|improve this answer





















    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "281"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcrypto.stackexchange.com%2fquestions%2f65963%2fwhat-does-constant-rate-mean-in-universal-composable-commitment-scheme%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



    Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






    share|improve this answer


























      4














      Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



      Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






      share|improve this answer
























        4












        4








        4






        Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



        Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






        share|improve this answer












        Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



        Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 18 '18 at 17:34









        Yehuda Lindell

        18.6k3560




        18.6k3560






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Cryptography Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcrypto.stackexchange.com%2fquestions%2f65963%2fwhat-does-constant-rate-mean-in-universal-composable-commitment-scheme%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            How do I know what Microsoft account the skydrive app is syncing to?

            Grease: Live!

            When does type information flow backwards in C++?