Is there a shortcut to mkdir foo and immediately cd into it?

This is something I do frequently

$ mkdir foo

$ cd foo

This works as a single command, but it's more keystrokes and saves no time.

$ mkdir foo && cd foo

Is there a shortcut for this?

Edit

With the use of help below, this seems to be the most elegant answer.

# ~/.bashrc

function mkcd {

  if [ ! -n "$1" ]; then

    echo "Enter a directory name"

  elif [ -d $1 ]; then

    echo "`$1' already exists"

  else

    mkdir $1 && cd $1

  fi

}

edited Jun 10 '14 at 22:59

gparyani

1,28472141

asked Jun 15 '10 at 14:22

macek

2,507143650

1

You can rename the function to mkdir if you use command mkdir $1 instead of just mkdir $1 in the function body.
– Andy
Jun 15 '10 at 14:50

2

(1) why not simply "mkdir $1 ; cd $1" instead of "&&"? that way the "cd" succeeds even if the "mkdir" fails, and you don't need the does-it-already-exist scaffolding. (2) as written your function won't work (to prompt you for a directory name). you need to put that in a separate "if" clause from the existence test (currently in "elif").
– quack quixote
Jun 15 '10 at 16:25

add a comment |

This is something I do frequently

$ mkdir foo

$ cd foo

This works as a single command, but it's more keystrokes and saves no time.

$ mkdir foo && cd foo

Is there a shortcut for this?

Edit

With the use of help below, this seems to be the most elegant answer.

# ~/.bashrc

function mkcd {

  if [ ! -n "$1" ]; then

    echo "Enter a directory name"

  elif [ -d $1 ]; then

    echo "`$1' already exists"

  else

    mkdir $1 && cd $1

  fi

}

edited Jun 10 '14 at 22:59

gparyani

1,28472141

asked Jun 15 '10 at 14:22

macek

2,507143650

1

You can rename the function to mkdir if you use command mkdir $1 instead of just mkdir $1 in the function body.
– Andy
Jun 15 '10 at 14:50

2

(1) why not simply "mkdir $1 ; cd $1" instead of "&&"? that way the "cd" succeeds even if the "mkdir" fails, and you don't need the does-it-already-exist scaffolding. (2) as written your function won't work (to prompt you for a directory name). you need to put that in a separate "if" clause from the existence test (currently in "elif").
– quack quixote
Jun 15 '10 at 16:25

add a comment |

This is something I do frequently

$ mkdir foo

$ cd foo

This works as a single command, but it's more keystrokes and saves no time.

$ mkdir foo && cd foo

Is there a shortcut for this?

Edit

With the use of help below, this seems to be the most elegant answer.

# ~/.bashrc

function mkcd {

  if [ ! -n "$1" ]; then

    echo "Enter a directory name"

  elif [ -d $1 ]; then

    echo "`$1' already exists"

  else

    mkdir $1 && cd $1

  fi

}

edited Jun 10 '14 at 22:59

gparyani

1,28472141

asked Jun 15 '10 at 14:22

macek

2,507143650

This is something I do frequently

$ mkdir foo

$ cd foo

This works as a single command, but it's more keystrokes and saves no time.

$ mkdir foo && cd foo

Is there a shortcut for this?

Edit

With the use of help below, this seems to be the most elegant answer.

# ~/.bashrc

function mkcd {

  if [ ! -n "$1" ]; then

    echo "Enter a directory name"

  elif [ -d $1 ]; then

    echo "`$1' already exists"

  else

    mkdir $1 && cd $1

  fi

}

command-line bash terminal shortcuts

edited Jun 10 '14 at 22:59

gparyani

1,28472141

asked Jun 15 '10 at 14:22

macek

2,507143650

edited Jun 10 '14 at 22:59

gparyani

1,28472141

asked Jun 15 '10 at 14:22

macek

2,507143650

edited Jun 10 '14 at 22:59

gparyani

1,28472141

edited Jun 10 '14 at 22:59

gparyani

1,28472141

edited Jun 10 '14 at 22:59

gparyani

1,28472141

asked Jun 15 '10 at 14:22

macek

2,507143650

asked Jun 15 '10 at 14:22

macek

2,507143650

asked Jun 15 '10 at 14:22

macek

2,507143650

1

You can rename the function to mkdir if you use command mkdir $1 instead of just mkdir $1 in the function body.
– Andy
Jun 15 '10 at 14:50

2

(1) why not simply "mkdir $1 ; cd $1" instead of "&&"? that way the "cd" succeeds even if the "mkdir" fails, and you don't need the does-it-already-exist scaffolding. (2) as written your function won't work (to prompt you for a directory name). you need to put that in a separate "if" clause from the existence test (currently in "elif").
– quack quixote
Jun 15 '10 at 16:25

add a comment |

1

You can rename the function to mkdir if you use command mkdir $1 instead of just mkdir $1 in the function body.
– Andy
Jun 15 '10 at 14:50

2

(1) why not simply "mkdir $1 ; cd $1" instead of "&&"? that way the "cd" succeeds even if the "mkdir" fails, and you don't need the does-it-already-exist scaffolding. (2) as written your function won't work (to prompt you for a directory name). you need to put that in a separate "if" clause from the existence test (currently in "elif").
– quack quixote
Jun 15 '10 at 16:25

You can rename the function to mkdir if you use command mkdir $1 instead of just mkdir $1 in the function body.
– Andy
Jun 15 '10 at 14:50

(1) why not simply "mkdir $1 ; cd $1" instead of "&&"? that way the "cd" succeeds even if the "mkdir" fails, and you don't need the does-it-already-exist scaffolding. (2) as written your function won't work (to prompt you for a directory name). you need to put that in a separate "if" clause from the existence test (currently in "elif").
– quack quixote
Jun 15 '10 at 16:25

add a comment |

9 Answers
9

active

oldest

votes

I'm no Linux/bash expert, but try putting this in your .bashrc.

function mkdir

{

  command mkdir $1 && cd $1

}

PS Thanks to Dennis for using command mkdir.

edited Jun 15 '10 at 15:29

answered Jun 15 '10 at 14:29

Andy

2,46431528

2

Instead of `which mkdir`, just use command mkdir.
– Dennis Williamson
Jun 15 '10 at 14:33

1

Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;)
– Andy
Jun 15 '10 at 14:49

2

command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command.
– grawity
Jun 15 '10 at 18:39

That also works for zsh btw
– Florian Loch
Dec 23 '14 at 11:37

add a comment |

The `bash`, `zsh` Shells

If you don't want another function to remember and don't mind bashisms:

$ mkdir /home/foo/doc/bar && cd $_

The $_ (dollar underscore) bash command variable contains the most recent parameter. So if a user were to type the following at the command line: echo foo bar && echo $_ baz, then the output would be as follows:

foo bar

bar baz

The `fish` Shell

In the fish shell, I would type the following:



> mkdir /home/foo/doc/bar

> cd alt + ↑

The alt key combined with either the up or the down arrow key will cycle through command parameter history.

edited Nov 10 '17 at 14:10

answered Aug 12 '11 at 11:26

kzh

2,22362231

4

This works in zsh too.
– Nabil Kadimi
Feb 16 '14 at 10:01

3

Can you explain what $_ is? Newbie here.
– arg20
Jun 25 '14 at 15:16

add a comment |

For oh-my-zsh users:
$ take 'directory_name'

Reference: https://github.com/robbyrussell/oh-my-zsh/wiki/Cheatsheet

edited Dec 9 '15 at 16:22

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

1

Can you explain this in more detail?
– bwDraco
Jul 13 '15 at 5:47

add a comment |

What about:

$ mkdir newdirname; cd $_

It's a bit easier than using &&, combining quack quixote's and kzh's answers.

answered Mar 14 '12 at 2:09

Alex

10912

24

The point of && is that cd will not be executed if the mkdir command fails
– slhck
Mar 14 '12 at 9:29

1

@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;.
– moala
Feb 2 '13 at 9:13

add a comment |

You can try something like this:

#!/bin/sh

mkdir $1 && cd $1

Save this script to some place that is in your path, for example, /usr/local/bin or ~/bin (you have to put this last one into your path in your ~/.profile file). Then you can simply call it.

answered Jun 15 '10 at 14:30

petersohn

2,18931423

4

how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script.
– Erik Allik
Oct 13 '13 at 16:15

add a comment |

$echo 'mkcd() { mkdir -p "$@" && cd "$_"; }' >> ~/.bashrc

$mkcd < pathtofolder/foldername >

answered Sep 19 '13 at 6:01

mshameers

15111

add a comment |

Here is a simple function I put in my ~/.config/fish/config.fish file which accomplishes this task:

function mkcd

    mkdir -pv $argv;

    cd $argv;

end

The -pv tag allows for the creation of directories with sub-directories.

edited Jul 25 '18 at 16:23

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

add a comment |

Depending on the desired outcome if the directory already exists.

Fail if directory already exists

mkcd() {

    mkdir $1 && cd $1

}

Change directory regardless

mkcd() {

    mkdir $1 ; cd $1

}

Usage
mkcd some/path/to/my/dir

edited Nov 19 '16 at 17:34

Olaf

1034

answered Oct 13 '15 at 11:51

bingles

1063

add a comment |

I found that the function below can only make one directory, if I want to make subdirectories at the same time, it doesn't work :

function mkdir

{

  command mkdir $1 && cd $1

}

So I changed it and now its working great!

function mkcd

{

  command mkdir -pv $1 && cd $1 && echo "Now in `pwd`"

}

answered Dec 20 '17 at 5:32

user5723841

add a comment |

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9 Answers
9

active

oldest

votes

9 Answers
9

active

oldest

votes

I'm no Linux/bash expert, but try putting this in your .bashrc.

function mkdir

{

  command mkdir $1 && cd $1

}

PS Thanks to Dennis for using command mkdir.

edited Jun 15 '10 at 15:29

answered Jun 15 '10 at 14:29

Andy

2,46431528

2

Instead of `which mkdir`, just use command mkdir.
– Dennis Williamson
Jun 15 '10 at 14:33

1

Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;)
– Andy
Jun 15 '10 at 14:49

2

command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command.
– grawity
Jun 15 '10 at 18:39

That also works for zsh btw
– Florian Loch
Dec 23 '14 at 11:37

add a comment |

I'm no Linux/bash expert, but try putting this in your .bashrc.

function mkdir

{

  command mkdir $1 && cd $1

}

PS Thanks to Dennis for using command mkdir.

edited Jun 15 '10 at 15:29

answered Jun 15 '10 at 14:29

Andy

2,46431528

2

Instead of `which mkdir`, just use command mkdir.
– Dennis Williamson
Jun 15 '10 at 14:33

1

Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;)
– Andy
Jun 15 '10 at 14:49

2

command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command.
– grawity
Jun 15 '10 at 18:39

That also works for zsh btw
– Florian Loch
Dec 23 '14 at 11:37

add a comment |

I'm no Linux/bash expert, but try putting this in your .bashrc.

function mkdir

{

  command mkdir $1 && cd $1

}

PS Thanks to Dennis for using command mkdir.

edited Jun 15 '10 at 15:29

answered Jun 15 '10 at 14:29

Andy

2,46431528

I'm no Linux/bash expert, but try putting this in your .bashrc.

function mkdir

{

  command mkdir $1 && cd $1

}

PS Thanks to Dennis for using command mkdir.

edited Jun 15 '10 at 15:29

answered Jun 15 '10 at 14:29

Andy

2,46431528

edited Jun 15 '10 at 15:29

answered Jun 15 '10 at 14:29

Andy

2,46431528

answered Jun 15 '10 at 14:29

Andy

2,46431528

answered Jun 15 '10 at 14:29

Andy

2,46431528

2

Instead of `which mkdir`, just use command mkdir.
– Dennis Williamson
Jun 15 '10 at 14:33

1

Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;)
– Andy
Jun 15 '10 at 14:49

2

command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command.
– grawity
Jun 15 '10 at 18:39

That also works for zsh btw
– Florian Loch
Dec 23 '14 at 11:37

add a comment |

2

Instead of `which mkdir`, just use command mkdir.
– Dennis Williamson
Jun 15 '10 at 14:33

1

Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;)
– Andy
Jun 15 '10 at 14:49

2

command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command.
– grawity
Jun 15 '10 at 18:39

That also works for zsh btw
– Florian Loch
Dec 23 '14 at 11:37

Instead of `which mkdir`, just use command mkdir.
– Dennis Williamson
Jun 15 '10 at 14:33

Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;)
– Andy
Jun 15 '10 at 14:49

command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command.
– grawity
Jun 15 '10 at 18:39

That also works for zsh btw
– Florian Loch
Dec 23 '14 at 11:37

add a comment |

The `bash`, `zsh` Shells

If you don't want another function to remember and don't mind bashisms:

$ mkdir /home/foo/doc/bar && cd $_

foo bar

bar baz

The `fish` Shell

In the fish shell, I would type the following:



> mkdir /home/foo/doc/bar

> cd alt + ↑

The alt key combined with either the up or the down arrow key will cycle through command parameter history.

edited Nov 10 '17 at 14:10

answered Aug 12 '11 at 11:26

kzh

2,22362231

4

This works in zsh too.
– Nabil Kadimi
Feb 16 '14 at 10:01

3

Can you explain what $_ is? Newbie here.
– arg20
Jun 25 '14 at 15:16

add a comment |

The `bash`, `zsh` Shells

If you don't want another function to remember and don't mind bashisms:

$ mkdir /home/foo/doc/bar && cd $_

foo bar

bar baz

The `fish` Shell

In the fish shell, I would type the following:



> mkdir /home/foo/doc/bar

> cd alt + ↑

The alt key combined with either the up or the down arrow key will cycle through command parameter history.

edited Nov 10 '17 at 14:10

answered Aug 12 '11 at 11:26

kzh

2,22362231

4

This works in zsh too.
– Nabil Kadimi
Feb 16 '14 at 10:01

3

Can you explain what $_ is? Newbie here.
– arg20
Jun 25 '14 at 15:16

add a comment |

The `bash`, `zsh` Shells

If you don't want another function to remember and don't mind bashisms:

$ mkdir /home/foo/doc/bar && cd $_

foo bar

bar baz

The `fish` Shell

In the fish shell, I would type the following:



> mkdir /home/foo/doc/bar

> cd alt + ↑

The alt key combined with either the up or the down arrow key will cycle through command parameter history.

edited Nov 10 '17 at 14:10

answered Aug 12 '11 at 11:26

kzh

2,22362231

The `bash`, `zsh` Shells

If you don't want another function to remember and don't mind bashisms:

$ mkdir /home/foo/doc/bar && cd $_

foo bar

bar baz

The `fish` Shell

In the fish shell, I would type the following:



> mkdir /home/foo/doc/bar

> cd alt + ↑

The alt key combined with either the up or the down arrow key will cycle through command parameter history.

edited Nov 10 '17 at 14:10

answered Aug 12 '11 at 11:26

kzh

2,22362231

edited Nov 10 '17 at 14:10

answered Aug 12 '11 at 11:26

kzh

2,22362231

answered Aug 12 '11 at 11:26

kzh

2,22362231

answered Aug 12 '11 at 11:26

kzh

2,22362231

4

This works in zsh too.
– Nabil Kadimi
Feb 16 '14 at 10:01

3

Can you explain what $_ is? Newbie here.
– arg20
Jun 25 '14 at 15:16

add a comment |

4

This works in zsh too.
– Nabil Kadimi
Feb 16 '14 at 10:01

3

Can you explain what $_ is? Newbie here.
– arg20
Jun 25 '14 at 15:16

This works in zsh too.
– Nabil Kadimi
Feb 16 '14 at 10:01

Can you explain what $_ is? Newbie here.
– arg20
Jun 25 '14 at 15:16

add a comment |

For oh-my-zsh users:
$ take 'directory_name'

Reference: https://github.com/robbyrussell/oh-my-zsh/wiki/Cheatsheet

edited Dec 9 '15 at 16:22

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

1

Can you explain this in more detail?
– bwDraco
Jul 13 '15 at 5:47

add a comment |

For oh-my-zsh users:
$ take 'directory_name'

Reference: https://github.com/robbyrussell/oh-my-zsh/wiki/Cheatsheet

edited Dec 9 '15 at 16:22

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

1

Can you explain this in more detail?
– bwDraco
Jul 13 '15 at 5:47

add a comment |

For oh-my-zsh users:
$ take 'directory_name'

Reference: https://github.com/robbyrussell/oh-my-zsh/wiki/Cheatsheet

edited Dec 9 '15 at 16:22

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

For oh-my-zsh users:
$ take 'directory_name'

Reference: https://github.com/robbyrussell/oh-my-zsh/wiki/Cheatsheet

edited Dec 9 '15 at 16:22

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

edited Dec 9 '15 at 16:22

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

answered Jul 12 '15 at 15:39

Avijit Gupta

26128

1

Can you explain this in more detail?
– bwDraco
Jul 13 '15 at 5:47

add a comment |

1

Can you explain this in more detail?
– bwDraco
Jul 13 '15 at 5:47

Can you explain this in more detail?
– bwDraco
Jul 13 '15 at 5:47

add a comment |

What about:

$ mkdir newdirname; cd $_

It's a bit easier than using &&, combining quack quixote's and kzh's answers.

answered Mar 14 '12 at 2:09

Alex

10912

24

The point of && is that cd will not be executed if the mkdir command fails
– slhck
Mar 14 '12 at 9:29

1

@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;.
– moala
Feb 2 '13 at 9:13

add a comment |

What about:

$ mkdir newdirname; cd $_

It's a bit easier than using &&, combining quack quixote's and kzh's answers.

answered Mar 14 '12 at 2:09

Alex

10912

24

The point of && is that cd will not be executed if the mkdir command fails
– slhck
Mar 14 '12 at 9:29

1

@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;.
– moala
Feb 2 '13 at 9:13

add a comment |

What about:

$ mkdir newdirname; cd $_

It's a bit easier than using &&, combining quack quixote's and kzh's answers.

answered Mar 14 '12 at 2:09

Alex

10912

What about:

$ mkdir newdirname; cd $_

It's a bit easier than using &&, combining quack quixote's and kzh's answers.

answered Mar 14 '12 at 2:09

Alex

10912

answered Mar 14 '12 at 2:09

Alex

10912

answered Mar 14 '12 at 2:09

Alex

10912

answered Mar 14 '12 at 2:09

Alex

10912

24

The point of && is that cd will not be executed if the mkdir command fails
– slhck
Mar 14 '12 at 9:29

1

@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;.
– moala
Feb 2 '13 at 9:13

add a comment |

24

The point of && is that cd will not be executed if the mkdir command fails
– slhck
Mar 14 '12 at 9:29

1

@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;.
– moala
Feb 2 '13 at 9:13

The point of && is that cd will not be executed if the mkdir command fails
– slhck
Mar 14 '12 at 9:29

@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;.
– moala
Feb 2 '13 at 9:13

add a comment |

You can try something like this:

#!/bin/sh

mkdir $1 && cd $1

Save this script to some place that is in your path, for example, /usr/local/bin or ~/bin (you have to put this last one into your path in your ~/.profile file). Then you can simply call it.

answered Jun 15 '10 at 14:30

petersohn

2,18931423

4

how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script.
– Erik Allik
Oct 13 '13 at 16:15

add a comment |

You can try something like this:

#!/bin/sh

mkdir $1 && cd $1

Save this script to some place that is in your path, for example, /usr/local/bin or ~/bin (you have to put this last one into your path in your ~/.profile file). Then you can simply call it.

answered Jun 15 '10 at 14:30

petersohn

2,18931423

4

how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script.
– Erik Allik
Oct 13 '13 at 16:15

add a comment |

You can try something like this:

#!/bin/sh

mkdir $1 && cd $1

Save this script to some place that is in your path, for example, /usr/local/bin or ~/bin (you have to put this last one into your path in your ~/.profile file). Then you can simply call it.

answered Jun 15 '10 at 14:30

petersohn

2,18931423

You can try something like this:

#!/bin/sh

mkdir $1 && cd $1

Save this script to some place that is in your path, for example, /usr/local/bin or ~/bin (you have to put this last one into your path in your ~/.profile file). Then you can simply call it.

answered Jun 15 '10 at 14:30

petersohn

2,18931423

answered Jun 15 '10 at 14:30

petersohn

2,18931423

answered Jun 15 '10 at 14:30

petersohn

2,18931423

answered Jun 15 '10 at 14:30

petersohn

2,18931423

4

how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script.
– Erik Allik
Oct 13 '13 at 16:15

add a comment |

4

how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script.
– Erik Allik
Oct 13 '13 at 16:15

how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script.
– Erik Allik
Oct 13 '13 at 16:15

add a comment |

$echo 'mkcd() { mkdir -p "$@" && cd "$_"; }' >> ~/.bashrc

$mkcd < pathtofolder/foldername >

answered Sep 19 '13 at 6:01

mshameers

15111

add a comment |

$echo 'mkcd() { mkdir -p "$@" && cd "$_"; }' >> ~/.bashrc

$mkcd < pathtofolder/foldername >

answered Sep 19 '13 at 6:01

mshameers

15111

add a comment |

$echo 'mkcd() { mkdir -p "$@" && cd "$_"; }' >> ~/.bashrc

$mkcd < pathtofolder/foldername >

answered Sep 19 '13 at 6:01

mshameers

15111

$echo 'mkcd() { mkdir -p "$@" && cd "$_"; }' >> ~/.bashrc

$mkcd < pathtofolder/foldername >

answered Sep 19 '13 at 6:01

mshameers

15111

answered Sep 19 '13 at 6:01

mshameers

15111

answered Sep 19 '13 at 6:01

mshameers

15111

answered Sep 19 '13 at 6:01

mshameers

15111

add a comment |

Here is a simple function I put in my ~/.config/fish/config.fish file which accomplishes this task:

function mkcd

    mkdir -pv $argv;

    cd $argv;

end

The -pv tag allows for the creation of directories with sub-directories.

edited Jul 25 '18 at 16:23

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

add a comment |

Here is a simple function I put in my ~/.config/fish/config.fish file which accomplishes this task:

function mkcd

    mkdir -pv $argv;

    cd $argv;

end

The -pv tag allows for the creation of directories with sub-directories.

edited Jul 25 '18 at 16:23

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

add a comment |

Here is a simple function I put in my ~/.config/fish/config.fish file which accomplishes this task:

function mkcd

    mkdir -pv $argv;

    cd $argv;

end

The -pv tag allows for the creation of directories with sub-directories.

edited Jul 25 '18 at 16:23

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

Here is a simple function I put in my ~/.config/fish/config.fish file which accomplishes this task:

function mkcd

    mkdir -pv $argv;

    cd $argv;

end

The -pv tag allows for the creation of directories with sub-directories.

edited Jul 25 '18 at 16:23

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

edited Jul 25 '18 at 16:23

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

answered Jul 23 '18 at 12:30

Alex Fenwood Hughes

113

add a comment |

Depending on the desired outcome if the directory already exists.

Fail if directory already exists

mkcd() {

    mkdir $1 && cd $1

}

Change directory regardless

mkcd() {

    mkdir $1 ; cd $1

}

Usage
mkcd some/path/to/my/dir

edited Nov 19 '16 at 17:34

Olaf

1034

answered Oct 13 '15 at 11:51

bingles

1063

add a comment |

Depending on the desired outcome if the directory already exists.

Fail if directory already exists

mkcd() {

    mkdir $1 && cd $1

}

Change directory regardless

mkcd() {

    mkdir $1 ; cd $1

}

Usage
mkcd some/path/to/my/dir

edited Nov 19 '16 at 17:34

Olaf

1034

answered Oct 13 '15 at 11:51

bingles

1063

add a comment |

Depending on the desired outcome if the directory already exists.

Fail if directory already exists

mkcd() {

    mkdir $1 && cd $1

}

Change directory regardless

mkcd() {

    mkdir $1 ; cd $1

}

Usage
mkcd some/path/to/my/dir

edited Nov 19 '16 at 17:34

Olaf

1034

answered Oct 13 '15 at 11:51

bingles

1063

Depending on the desired outcome if the directory already exists.

Fail if directory already exists

mkcd() {

    mkdir $1 && cd $1

}

Change directory regardless

mkcd() {

    mkdir $1 ; cd $1

}

Usage
mkcd some/path/to/my/dir

edited Nov 19 '16 at 17:34

Olaf

1034

answered Oct 13 '15 at 11:51

bingles

1063

edited Nov 19 '16 at 17:34

Olaf

1034

edited Nov 19 '16 at 17:34

Olaf

1034

edited Nov 19 '16 at 17:34

Olaf

1034

answered Oct 13 '15 at 11:51

bingles

1063

answered Oct 13 '15 at 11:51

bingles

1063

answered Oct 13 '15 at 11:51

bingles

1063

add a comment |

I found that the function below can only make one directory, if I want to make subdirectories at the same time, it doesn't work :

function mkdir

{

  command mkdir $1 && cd $1

}

So I changed it and now its working great!

function mkcd

{

  command mkdir -pv $1 && cd $1 && echo "Now in `pwd`"

}

answered Dec 20 '17 at 5:32

user5723841

add a comment |

I found that the function below can only make one directory, if I want to make subdirectories at the same time, it doesn't work :

function mkdir

{

  command mkdir $1 && cd $1

}

So I changed it and now its working great!

function mkcd

{

  command mkdir -pv $1 && cd $1 && echo "Now in `pwd`"

}

answered Dec 20 '17 at 5:32

user5723841

add a comment |

I found that the function below can only make one directory, if I want to make subdirectories at the same time, it doesn't work :

function mkdir

{

  command mkdir $1 && cd $1

}

So I changed it and now its working great!

function mkcd

{

  command mkdir -pv $1 && cd $1 && echo "Now in `pwd`"

}

answered Dec 20 '17 at 5:32

user5723841

I found that the function below can only make one directory, if I want to make subdirectories at the same time, it doesn't work :

function mkdir

{

  command mkdir $1 && cd $1

}

So I changed it and now its working great!

function mkcd

{

  command mkdir -pv $1 && cd $1 && echo "Now in `pwd`"

}

answered Dec 20 '17 at 5:32

user5723841

answered Dec 20 '17 at 5:32

user5723841

answered Dec 20 '17 at 5:32

user5723841

answered Dec 20 '17 at 5:32

user5723841

add a comment |

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