how do you transpose more than 2 matrices [closed]











up vote
0
down vote

favorite












Sorry for the stupid question. How do you transpose more than 2 matrices.



i.e. $(ABCDE)'=$










share|cite|improve this question









New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    This is akin to the socks-shoes property. Write the product in reverse order with transposes.
    – Sean Roberson
    Nov 13 at 17:25










  • so it will be E'D'C'B'A'
    – user9903833
    Nov 13 at 17:27










  • @user9903833 Yes, that's right
    – Rushabh Mehta
    Nov 13 at 17:31















up vote
0
down vote

favorite












Sorry for the stupid question. How do you transpose more than 2 matrices.



i.e. $(ABCDE)'=$










share|cite|improve this question









New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    This is akin to the socks-shoes property. Write the product in reverse order with transposes.
    – Sean Roberson
    Nov 13 at 17:25










  • so it will be E'D'C'B'A'
    – user9903833
    Nov 13 at 17:27










  • @user9903833 Yes, that's right
    – Rushabh Mehta
    Nov 13 at 17:31













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Sorry for the stupid question. How do you transpose more than 2 matrices.



i.e. $(ABCDE)'=$










share|cite|improve this question









New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Sorry for the stupid question. How do you transpose more than 2 matrices.



i.e. $(ABCDE)'=$







linear-algebra






share|cite|improve this question









New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited Nov 13 at 17:33









Bernard

115k637108




115k637108






New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Nov 13 at 17:23









user9903833

6




6




New contributor




user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






user9903833 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    This is akin to the socks-shoes property. Write the product in reverse order with transposes.
    – Sean Roberson
    Nov 13 at 17:25










  • so it will be E'D'C'B'A'
    – user9903833
    Nov 13 at 17:27










  • @user9903833 Yes, that's right
    – Rushabh Mehta
    Nov 13 at 17:31














  • 1




    This is akin to the socks-shoes property. Write the product in reverse order with transposes.
    – Sean Roberson
    Nov 13 at 17:25










  • so it will be E'D'C'B'A'
    – user9903833
    Nov 13 at 17:27










  • @user9903833 Yes, that's right
    – Rushabh Mehta
    Nov 13 at 17:31








1




1




This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25




This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25












so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27




so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27












@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31




@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31










1 Answer
1






active

oldest

votes

















up vote
2
down vote













if $(AB)^T = B^TA^T$ and matrix multipication is associative.



$(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote













    if $(AB)^T = B^TA^T$ and matrix multipication is associative.



    $(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.






    share|cite|improve this answer

























      up vote
      2
      down vote













      if $(AB)^T = B^TA^T$ and matrix multipication is associative.



      $(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.






      share|cite|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        if $(AB)^T = B^TA^T$ and matrix multipication is associative.



        $(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.






        share|cite|improve this answer












        if $(AB)^T = B^TA^T$ and matrix multipication is associative.



        $(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 13 at 17:26









        Doug M

        42.5k31752




        42.5k31752















            Popular posts from this blog

            How do I know what Microsoft account the skydrive app is syncing to?

            Grease: Live!

            When does type information flow backwards in C++?