Anti-aromatic or Non-aromatic [closed]












1












$begingroup$


Please tell if the 2 given conpound are Anti-aromatic or Non-aromatic,
enter image description here



I have confusions arising due to incosistent facts all around internet some of them are as follow :



1.) Arguments for Cyclopropenyl Anion



a.) Wikipedia which under the heading of "Effects on reactivity"
clearly states that :




"However, the cyclopropenyl anion has 4 π electrons in a cyclic system
and in fact has a substantially higher pKa than 1-propene because it
is antiaromatic and thus destabilized"




b.) This Answer on ChemSE which clearly states that its Non-Aromatic in
Nature



c.) Also this NEPTL site which clearly states that:




Cyclopropene is not aromatic because one of its ring atoms is sp3
hybridized so it does not fulfill the criterion for aromaticity. But
the cyclopropenyl cation is aromatic because it has an uninterrupted
ring of p-orbital and (4n+2) π-system. The cyclopropenyl anion is
antiaromatic as it has (4n) π-system
.




2.) Arguments for cycloheptatrienyl anion



a.) This Question on ChemSE where the same question have 2 deflecting answer this answer is saying is that the anoin is antiaromatic and this states that the anion is nonaromatic



b.) Also my book (solomons and fryhle organic chemistry adapted for JEE) gives this as Antiaromatic



I don't know which one is correct, please help by providing a comprehensive answer with a reason that can be applied everywhere in such questions.



EDIT: Hello the one who closed the question can I ask the reason for closing as much I can do I abid by this guideline I asked my question straigthformward and then presented my research please tell me why my question is put on hold, I seek answers










share|improve this question











$endgroup$



closed as unclear what you're asking by Mithoron, user55119, A.K., andselisk, Todd Minehardt Feb 25 at 0:29


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • 1




    $begingroup$
    Basically the SE answer you mention should fiv your current Q as well. Given the existance of a species that results in antiaromaticuty, then ist that the species avoid it. The key is that antiaromaticity is forced, it serves to determine if a formally conjugated system does indeed undergo delocalosation, not to establish its existence.
    $endgroup$
    – Alchimista
    Feb 24 at 13:44








  • 1




    $begingroup$
    Well, in the past antiaromaticity was attributed to about as many structures as aromaticity, thing is it pretty much doesn't work at all.
    $endgroup$
    – Mithoron
    Feb 24 at 18:53










  • $begingroup$
    chemistry.stackexchange.com/questions/45040/…
    $endgroup$
    – Mithoron
    Feb 24 at 19:05






  • 1




    $begingroup$
    It would be better to just make a post about when antiaromaticity actually applies, but as you noticed, you could get pretty much any answer, ranging from not applying to anything to everything one might suspect. BTW it's technically a follow-up of two old posts, but such question shouldn't just repeat old question.
    $endgroup$
    – Mithoron
    Feb 25 at 2:20






  • 1




    $begingroup$
    Both of them are antiaromatic as both of them has 4n π electrons.Also,I'm going to suggest you that if have to choose between internet and books,you should choose books as reference because there are a lot of people on the internet who might not know everything but nonetheless they post about that topic i.e. there's no one to verify all the stuff on the internet but the books are genuine.
    $endgroup$
    – Abner Alfred Thompson
    Feb 25 at 3:14
















1












$begingroup$


Please tell if the 2 given conpound are Anti-aromatic or Non-aromatic,
enter image description here



I have confusions arising due to incosistent facts all around internet some of them are as follow :



1.) Arguments for Cyclopropenyl Anion



a.) Wikipedia which under the heading of "Effects on reactivity"
clearly states that :




"However, the cyclopropenyl anion has 4 π electrons in a cyclic system
and in fact has a substantially higher pKa than 1-propene because it
is antiaromatic and thus destabilized"




b.) This Answer on ChemSE which clearly states that its Non-Aromatic in
Nature



c.) Also this NEPTL site which clearly states that:




Cyclopropene is not aromatic because one of its ring atoms is sp3
hybridized so it does not fulfill the criterion for aromaticity. But
the cyclopropenyl cation is aromatic because it has an uninterrupted
ring of p-orbital and (4n+2) π-system. The cyclopropenyl anion is
antiaromatic as it has (4n) π-system
.




2.) Arguments for cycloheptatrienyl anion



a.) This Question on ChemSE where the same question have 2 deflecting answer this answer is saying is that the anoin is antiaromatic and this states that the anion is nonaromatic



b.) Also my book (solomons and fryhle organic chemistry adapted for JEE) gives this as Antiaromatic



I don't know which one is correct, please help by providing a comprehensive answer with a reason that can be applied everywhere in such questions.



EDIT: Hello the one who closed the question can I ask the reason for closing as much I can do I abid by this guideline I asked my question straigthformward and then presented my research please tell me why my question is put on hold, I seek answers










share|improve this question











$endgroup$



closed as unclear what you're asking by Mithoron, user55119, A.K., andselisk, Todd Minehardt Feb 25 at 0:29


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • 1




    $begingroup$
    Basically the SE answer you mention should fiv your current Q as well. Given the existance of a species that results in antiaromaticuty, then ist that the species avoid it. The key is that antiaromaticity is forced, it serves to determine if a formally conjugated system does indeed undergo delocalosation, not to establish its existence.
    $endgroup$
    – Alchimista
    Feb 24 at 13:44








  • 1




    $begingroup$
    Well, in the past antiaromaticity was attributed to about as many structures as aromaticity, thing is it pretty much doesn't work at all.
    $endgroup$
    – Mithoron
    Feb 24 at 18:53










  • $begingroup$
    chemistry.stackexchange.com/questions/45040/…
    $endgroup$
    – Mithoron
    Feb 24 at 19:05






  • 1




    $begingroup$
    It would be better to just make a post about when antiaromaticity actually applies, but as you noticed, you could get pretty much any answer, ranging from not applying to anything to everything one might suspect. BTW it's technically a follow-up of two old posts, but such question shouldn't just repeat old question.
    $endgroup$
    – Mithoron
    Feb 25 at 2:20






  • 1




    $begingroup$
    Both of them are antiaromatic as both of them has 4n π electrons.Also,I'm going to suggest you that if have to choose between internet and books,you should choose books as reference because there are a lot of people on the internet who might not know everything but nonetheless they post about that topic i.e. there's no one to verify all the stuff on the internet but the books are genuine.
    $endgroup$
    – Abner Alfred Thompson
    Feb 25 at 3:14














1












1








1





$begingroup$


Please tell if the 2 given conpound are Anti-aromatic or Non-aromatic,
enter image description here



I have confusions arising due to incosistent facts all around internet some of them are as follow :



1.) Arguments for Cyclopropenyl Anion



a.) Wikipedia which under the heading of "Effects on reactivity"
clearly states that :




"However, the cyclopropenyl anion has 4 π electrons in a cyclic system
and in fact has a substantially higher pKa than 1-propene because it
is antiaromatic and thus destabilized"




b.) This Answer on ChemSE which clearly states that its Non-Aromatic in
Nature



c.) Also this NEPTL site which clearly states that:




Cyclopropene is not aromatic because one of its ring atoms is sp3
hybridized so it does not fulfill the criterion for aromaticity. But
the cyclopropenyl cation is aromatic because it has an uninterrupted
ring of p-orbital and (4n+2) π-system. The cyclopropenyl anion is
antiaromatic as it has (4n) π-system
.




2.) Arguments for cycloheptatrienyl anion



a.) This Question on ChemSE where the same question have 2 deflecting answer this answer is saying is that the anoin is antiaromatic and this states that the anion is nonaromatic



b.) Also my book (solomons and fryhle organic chemistry adapted for JEE) gives this as Antiaromatic



I don't know which one is correct, please help by providing a comprehensive answer with a reason that can be applied everywhere in such questions.



EDIT: Hello the one who closed the question can I ask the reason for closing as much I can do I abid by this guideline I asked my question straigthformward and then presented my research please tell me why my question is put on hold, I seek answers










share|improve this question











$endgroup$




Please tell if the 2 given conpound are Anti-aromatic or Non-aromatic,
enter image description here



I have confusions arising due to incosistent facts all around internet some of them are as follow :



1.) Arguments for Cyclopropenyl Anion



a.) Wikipedia which under the heading of "Effects on reactivity"
clearly states that :




"However, the cyclopropenyl anion has 4 π electrons in a cyclic system
and in fact has a substantially higher pKa than 1-propene because it
is antiaromatic and thus destabilized"




b.) This Answer on ChemSE which clearly states that its Non-Aromatic in
Nature



c.) Also this NEPTL site which clearly states that:




Cyclopropene is not aromatic because one of its ring atoms is sp3
hybridized so it does not fulfill the criterion for aromaticity. But
the cyclopropenyl cation is aromatic because it has an uninterrupted
ring of p-orbital and (4n+2) π-system. The cyclopropenyl anion is
antiaromatic as it has (4n) π-system
.




2.) Arguments for cycloheptatrienyl anion



a.) This Question on ChemSE where the same question have 2 deflecting answer this answer is saying is that the anoin is antiaromatic and this states that the anion is nonaromatic



b.) Also my book (solomons and fryhle organic chemistry adapted for JEE) gives this as Antiaromatic



I don't know which one is correct, please help by providing a comprehensive answer with a reason that can be applied everywhere in such questions.



EDIT: Hello the one who closed the question can I ask the reason for closing as much I can do I abid by this guideline I asked my question straigthformward and then presented my research please tell me why my question is put on hold, I seek answers







organic-chemistry aromaticity






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 25 at 1:51







Advil Sell

















asked Feb 24 at 10:52









Advil SellAdvil Sell

373113




373113




closed as unclear what you're asking by Mithoron, user55119, A.K., andselisk, Todd Minehardt Feb 25 at 0:29


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.









closed as unclear what you're asking by Mithoron, user55119, A.K., andselisk, Todd Minehardt Feb 25 at 0:29


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 1




    $begingroup$
    Basically the SE answer you mention should fiv your current Q as well. Given the existance of a species that results in antiaromaticuty, then ist that the species avoid it. The key is that antiaromaticity is forced, it serves to determine if a formally conjugated system does indeed undergo delocalosation, not to establish its existence.
    $endgroup$
    – Alchimista
    Feb 24 at 13:44








  • 1




    $begingroup$
    Well, in the past antiaromaticity was attributed to about as many structures as aromaticity, thing is it pretty much doesn't work at all.
    $endgroup$
    – Mithoron
    Feb 24 at 18:53










  • $begingroup$
    chemistry.stackexchange.com/questions/45040/…
    $endgroup$
    – Mithoron
    Feb 24 at 19:05






  • 1




    $begingroup$
    It would be better to just make a post about when antiaromaticity actually applies, but as you noticed, you could get pretty much any answer, ranging from not applying to anything to everything one might suspect. BTW it's technically a follow-up of two old posts, but such question shouldn't just repeat old question.
    $endgroup$
    – Mithoron
    Feb 25 at 2:20






  • 1




    $begingroup$
    Both of them are antiaromatic as both of them has 4n π electrons.Also,I'm going to suggest you that if have to choose between internet and books,you should choose books as reference because there are a lot of people on the internet who might not know everything but nonetheless they post about that topic i.e. there's no one to verify all the stuff on the internet but the books are genuine.
    $endgroup$
    – Abner Alfred Thompson
    Feb 25 at 3:14














  • 1




    $begingroup$
    Basically the SE answer you mention should fiv your current Q as well. Given the existance of a species that results in antiaromaticuty, then ist that the species avoid it. The key is that antiaromaticity is forced, it serves to determine if a formally conjugated system does indeed undergo delocalosation, not to establish its existence.
    $endgroup$
    – Alchimista
    Feb 24 at 13:44








  • 1




    $begingroup$
    Well, in the past antiaromaticity was attributed to about as many structures as aromaticity, thing is it pretty much doesn't work at all.
    $endgroup$
    – Mithoron
    Feb 24 at 18:53










  • $begingroup$
    chemistry.stackexchange.com/questions/45040/…
    $endgroup$
    – Mithoron
    Feb 24 at 19:05






  • 1




    $begingroup$
    It would be better to just make a post about when antiaromaticity actually applies, but as you noticed, you could get pretty much any answer, ranging from not applying to anything to everything one might suspect. BTW it's technically a follow-up of two old posts, but such question shouldn't just repeat old question.
    $endgroup$
    – Mithoron
    Feb 25 at 2:20






  • 1




    $begingroup$
    Both of them are antiaromatic as both of them has 4n π electrons.Also,I'm going to suggest you that if have to choose between internet and books,you should choose books as reference because there are a lot of people on the internet who might not know everything but nonetheless they post about that topic i.e. there's no one to verify all the stuff on the internet but the books are genuine.
    $endgroup$
    – Abner Alfred Thompson
    Feb 25 at 3:14








1




1




$begingroup$
Basically the SE answer you mention should fiv your current Q as well. Given the existance of a species that results in antiaromaticuty, then ist that the species avoid it. The key is that antiaromaticity is forced, it serves to determine if a formally conjugated system does indeed undergo delocalosation, not to establish its existence.
$endgroup$
– Alchimista
Feb 24 at 13:44






$begingroup$
Basically the SE answer you mention should fiv your current Q as well. Given the existance of a species that results in antiaromaticuty, then ist that the species avoid it. The key is that antiaromaticity is forced, it serves to determine if a formally conjugated system does indeed undergo delocalosation, not to establish its existence.
$endgroup$
– Alchimista
Feb 24 at 13:44






1




1




$begingroup$
Well, in the past antiaromaticity was attributed to about as many structures as aromaticity, thing is it pretty much doesn't work at all.
$endgroup$
– Mithoron
Feb 24 at 18:53




$begingroup$
Well, in the past antiaromaticity was attributed to about as many structures as aromaticity, thing is it pretty much doesn't work at all.
$endgroup$
– Mithoron
Feb 24 at 18:53












$begingroup$
chemistry.stackexchange.com/questions/45040/…
$endgroup$
– Mithoron
Feb 24 at 19:05




$begingroup$
chemistry.stackexchange.com/questions/45040/…
$endgroup$
– Mithoron
Feb 24 at 19:05




1




1




$begingroup$
It would be better to just make a post about when antiaromaticity actually applies, but as you noticed, you could get pretty much any answer, ranging from not applying to anything to everything one might suspect. BTW it's technically a follow-up of two old posts, but such question shouldn't just repeat old question.
$endgroup$
– Mithoron
Feb 25 at 2:20




$begingroup$
It would be better to just make a post about when antiaromaticity actually applies, but as you noticed, you could get pretty much any answer, ranging from not applying to anything to everything one might suspect. BTW it's technically a follow-up of two old posts, but such question shouldn't just repeat old question.
$endgroup$
– Mithoron
Feb 25 at 2:20




1




1




$begingroup$
Both of them are antiaromatic as both of them has 4n π electrons.Also,I'm going to suggest you that if have to choose between internet and books,you should choose books as reference because there are a lot of people on the internet who might not know everything but nonetheless they post about that topic i.e. there's no one to verify all the stuff on the internet but the books are genuine.
$endgroup$
– Abner Alfred Thompson
Feb 25 at 3:14




$begingroup$
Both of them are antiaromatic as both of them has 4n π electrons.Also,I'm going to suggest you that if have to choose between internet and books,you should choose books as reference because there are a lot of people on the internet who might not know everything but nonetheless they post about that topic i.e. there's no one to verify all the stuff on the internet but the books are genuine.
$endgroup$
– Abner Alfred Thompson
Feb 25 at 3:14










1 Answer
1






active

oldest

votes


















2












$begingroup$

Whenever you want a definition of a chemical concept, you should refer to the IUPAC's Gold Book which in this case states that antiaromatic compounds are




compounds that contain 4 n(n ≠ 0) π-electrons in a cyclic planar, or nearly planar, system of alternating single and double bonds, e.g. cyclobuta-1,3-diene.




A corollary to this rule is that all the atoms must have an sp2-hybridization, so the orbitals can overlap. However, the carbon bearing the negative charge has an sp3-hybridization, i.e. they does not count as π-electrons but σ-electrons and that breaks the rule of alternating single and double bonds. So both anions are non-aromatic.



Edited after the OP opened my eyes on a big mistake I had made in answering his question. Sorry about that.






share|improve this answer











$endgroup$













  • $begingroup$
    as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 13:41










  • $begingroup$
    I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
    $endgroup$
    – Advil Sell
    Feb 24 at 14:17








  • 1




    $begingroup$
    Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
    $endgroup$
    – SteffX
    Feb 24 at 14:30










  • $begingroup$
    oh...Nice I think I got your point thanks for the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 15:42


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Whenever you want a definition of a chemical concept, you should refer to the IUPAC's Gold Book which in this case states that antiaromatic compounds are




compounds that contain 4 n(n ≠ 0) π-electrons in a cyclic planar, or nearly planar, system of alternating single and double bonds, e.g. cyclobuta-1,3-diene.




A corollary to this rule is that all the atoms must have an sp2-hybridization, so the orbitals can overlap. However, the carbon bearing the negative charge has an sp3-hybridization, i.e. they does not count as π-electrons but σ-electrons and that breaks the rule of alternating single and double bonds. So both anions are non-aromatic.



Edited after the OP opened my eyes on a big mistake I had made in answering his question. Sorry about that.






share|improve this answer











$endgroup$













  • $begingroup$
    as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 13:41










  • $begingroup$
    I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
    $endgroup$
    – Advil Sell
    Feb 24 at 14:17








  • 1




    $begingroup$
    Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
    $endgroup$
    – SteffX
    Feb 24 at 14:30










  • $begingroup$
    oh...Nice I think I got your point thanks for the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 15:42
















2












$begingroup$

Whenever you want a definition of a chemical concept, you should refer to the IUPAC's Gold Book which in this case states that antiaromatic compounds are




compounds that contain 4 n(n ≠ 0) π-electrons in a cyclic planar, or nearly planar, system of alternating single and double bonds, e.g. cyclobuta-1,3-diene.




A corollary to this rule is that all the atoms must have an sp2-hybridization, so the orbitals can overlap. However, the carbon bearing the negative charge has an sp3-hybridization, i.e. they does not count as π-electrons but σ-electrons and that breaks the rule of alternating single and double bonds. So both anions are non-aromatic.



Edited after the OP opened my eyes on a big mistake I had made in answering his question. Sorry about that.






share|improve this answer











$endgroup$













  • $begingroup$
    as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 13:41










  • $begingroup$
    I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
    $endgroup$
    – Advil Sell
    Feb 24 at 14:17








  • 1




    $begingroup$
    Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
    $endgroup$
    – SteffX
    Feb 24 at 14:30










  • $begingroup$
    oh...Nice I think I got your point thanks for the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 15:42














2












2








2





$begingroup$

Whenever you want a definition of a chemical concept, you should refer to the IUPAC's Gold Book which in this case states that antiaromatic compounds are




compounds that contain 4 n(n ≠ 0) π-electrons in a cyclic planar, or nearly planar, system of alternating single and double bonds, e.g. cyclobuta-1,3-diene.




A corollary to this rule is that all the atoms must have an sp2-hybridization, so the orbitals can overlap. However, the carbon bearing the negative charge has an sp3-hybridization, i.e. they does not count as π-electrons but σ-electrons and that breaks the rule of alternating single and double bonds. So both anions are non-aromatic.



Edited after the OP opened my eyes on a big mistake I had made in answering his question. Sorry about that.






share|improve this answer











$endgroup$



Whenever you want a definition of a chemical concept, you should refer to the IUPAC's Gold Book which in this case states that antiaromatic compounds are




compounds that contain 4 n(n ≠ 0) π-electrons in a cyclic planar, or nearly planar, system of alternating single and double bonds, e.g. cyclobuta-1,3-diene.




A corollary to this rule is that all the atoms must have an sp2-hybridization, so the orbitals can overlap. However, the carbon bearing the negative charge has an sp3-hybridization, i.e. they does not count as π-electrons but σ-electrons and that breaks the rule of alternating single and double bonds. So both anions are non-aromatic.



Edited after the OP opened my eyes on a big mistake I had made in answering his question. Sorry about that.







share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 24 at 14:06

























answered Feb 24 at 13:28









SteffXSteffX

1,94439




1,94439












  • $begingroup$
    as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 13:41










  • $begingroup$
    I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
    $endgroup$
    – Advil Sell
    Feb 24 at 14:17








  • 1




    $begingroup$
    Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
    $endgroup$
    – SteffX
    Feb 24 at 14:30










  • $begingroup$
    oh...Nice I think I got your point thanks for the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 15:42


















  • $begingroup$
    as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 13:41










  • $begingroup$
    I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
    $endgroup$
    – Advil Sell
    Feb 24 at 14:17








  • 1




    $begingroup$
    Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
    $endgroup$
    – SteffX
    Feb 24 at 14:30










  • $begingroup$
    oh...Nice I think I got your point thanks for the answer
    $endgroup$
    – Advil Sell
    Feb 24 at 15:42
















$begingroup$
as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
$endgroup$
– Advil Sell
Feb 24 at 13:41




$begingroup$
as i know that alternating single and double bond means conjugation but as chemistry.stackexchange.com/a/51470/73826 this answer suggest the carbanion moves out of plane and hence can't remain in conjugation ......please clear this in the answer
$endgroup$
– Advil Sell
Feb 24 at 13:41












$begingroup$
I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
$endgroup$
– Advil Sell
Feb 24 at 14:17






$begingroup$
I dont know if I am wrong that some ring with a -ve charge are aromatic in which the electrons are considered as $pi$ electron and thus the congugation is present , can you explain why they aren't considered as $pi$ electrons here ???
$endgroup$
– Advil Sell
Feb 24 at 14:17






1




1




$begingroup$
Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
$endgroup$
– SteffX
Feb 24 at 14:30




$begingroup$
Oh right, I get it. You actually wonder why the cyclopentadienyl anion is aromatic, and the anion center is sp2 in that case, whereas it is not in the case with cycloheptadienyl anion. Well hybridization occurs only if it helps getting a lower potential energy or, in other terms, if there is an incentive to do so. There is an incentive to change hybridization to go aromatic, but not to go antiaromatic.
$endgroup$
– SteffX
Feb 24 at 14:30












$begingroup$
oh...Nice I think I got your point thanks for the answer
$endgroup$
– Advil Sell
Feb 24 at 15:42




$begingroup$
oh...Nice I think I got your point thanks for the answer
$endgroup$
– Advil Sell
Feb 24 at 15:42



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