Indefinite integral of $lnbig(arccos(5x)/arcsin(3x)big)$ [closed]
2
$begingroup$
Find $$int,lnleft(frac{arccos(5x)}{arcsin(3x)}right),text{d}x,.$$
Can anyone find this one for me please or at least give me the steps to work it out please.
calculus integration trigonometry logarithms indefinite-integrals
edited Dec 14 '18 at 22:01
Jam
4,98421431
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
$endgroup$
closed as off-topic by Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy Dec 14 '18 at 20:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
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show 4 more comments
2
$begingroup$
Find $$int,lnleft(frac{arccos(5x)}{arcsin(3x)}right),text{d}x,.$$
Can anyone find this one for me please or at least give me the steps to work it out please.
calculus integration trigonometry logarithms indefinite-integrals
edited Dec 14 '18 at 22:01
Jam
4,98421431
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
$endgroup$
closed as off-topic by Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy Dec 14 '18 at 20:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
Use proofwiki.org/wiki/Difference_of_Logarithms and mathworld.wolfram.com/IntegrationbyParts.html
$endgroup$
– lab bhattacharjee
Dec 14 '18 at 17:24
$begingroup$
This may be useful.
$endgroup$
– Decaf-Math
Dec 14 '18 at 17:36
$begingroup$
@Decaf-Math this link 1) isn't useful because it cannot give the method to follow 2) I have tried it with a failure to give an answer
$endgroup$
– Jean Marie
Dec 14 '18 at 17:56
2
$begingroup$
@Gady-ManuelAlaoui Normally I would respect the hold and not comment, but this question is so tricky that I feel it is unreasonable to expect you to "show your work". I will give a series of comments that provide an outline of the solution.
$endgroup$
– user2661923
Dec 14 '18 at 20:36
1
$begingroup$
Using integration by parts, $I = ln(u)cos(u) - int [(cos u)/u] ;du.$ Re one of my previous comments, this completes the problem, at least as far as $int ln[text{arccos}(x)] ;dx$ is concerned.
$endgroup$
– user2661923
Dec 14 '18 at 20:50
|
show 4 more comments
2
2
2
1
$begingroup$
Find $$int,lnleft(frac{arccos(5x)}{arcsin(3x)}right),text{d}x,.$$
Can anyone find this one for me please or at least give me the steps to work it out please.
calculus integration trigonometry logarithms indefinite-integrals
edited Dec 14 '18 at 22:01
Jam
4,98421431
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
$endgroup$
Find $$int,lnleft(frac{arccos(5x)}{arcsin(3x)}right),text{d}x,.$$
Can anyone find this one for me please or at least give me the steps to work it out please.
calculus integration trigonometry logarithms indefinite-integrals
calculus integration trigonometry logarithms indefinite-integrals
edited Dec 14 '18 at 22:01
Jam
4,98421431
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
edited Dec 14 '18 at 22:01
Jam
4,98421431
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
edited Dec 14 '18 at 22:01
Jam
4,98421431
edited Dec 14 '18 at 22:01
Jam
4,98421431
edited Dec 14 '18 at 22:01
Jam
4,98421431
4,98421431
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
asked Dec 14 '18 at 17:22
Gady-Manuel AlaouiGady-Manuel Alaoui
171
171
closed as off-topic by Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy Dec 14 '18 at 20:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy Dec 14 '18 at 20:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Arnaud D., Mostafa Ayaz, user10354138, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
Use proofwiki.org/wiki/Difference_of_Logarithms and mathworld.wolfram.com/IntegrationbyParts.html
$endgroup$
– lab bhattacharjee
Dec 14 '18 at 17:24
$begingroup$
This may be useful.
$endgroup$
– Decaf-Math
Dec 14 '18 at 17:36
$begingroup$
@Decaf-Math this link 1) isn't useful because it cannot give the method to follow 2) I have tried it with a failure to give an answer
$endgroup$
– Jean Marie
Dec 14 '18 at 17:56
2
$begingroup$
@Gady-ManuelAlaoui Normally I would respect the hold and not comment, but this question is so tricky that I feel it is unreasonable to expect you to "show your work". I will give a series of comments that provide an outline of the solution.
$endgroup$
– user2661923
Dec 14 '18 at 20:36
1
$begingroup$
Using integration by parts, $I = ln(u)cos(u) - int [(cos u)/u] ;du.$ Re one of my previous comments, this completes the problem, at least as far as $int ln[text{arccos}(x)] ;dx$ is concerned.
$endgroup$
– user2661923
Dec 14 '18 at 20:50
|
show 4 more comments
1
$begingroup$
Use proofwiki.org/wiki/Difference_of_Logarithms and mathworld.wolfram.com/IntegrationbyParts.html
$endgroup$
– lab bhattacharjee
Dec 14 '18 at 17:24
$begingroup$
This may be useful.
$endgroup$
– Decaf-Math
Dec 14 '18 at 17:36
$begingroup$
@Decaf-Math this link 1) isn't useful because it cannot give the method to follow 2) I have tried it with a failure to give an answer
$endgroup$
– Jean Marie
Dec 14 '18 at 17:56
2
$begingroup$
@Gady-ManuelAlaoui Normally I would respect the hold and not comment, but this question is so tricky that I feel it is unreasonable to expect you to "show your work". I will give a series of comments that provide an outline of the solution.
$endgroup$
– user2661923
Dec 14 '18 at 20:36
1
$begingroup$
Using integration by parts, $I = ln(u)cos(u) - int [(cos u)/u] ;du.$ Re one of my previous comments, this completes the problem, at least as far as $int ln[text{arccos}(x)] ;dx$ is concerned.
$endgroup$
– user2661923
Dec 14 '18 at 20:50
1
1
$begingroup$
Use proofwiki.org/wiki/Difference_of_Logarithms and mathworld.wolfram.com/IntegrationbyParts.html
$endgroup$
– lab bhattacharjee
Dec 14 '18 at 17:24
$begingroup$
Use proofwiki.org/wiki/Difference_of_Logarithms and mathworld.wolfram.com/IntegrationbyParts.html
$endgroup$
– lab bhattacharjee
Dec 14 '18 at 17:24
$begingroup$
This may be useful.
$endgroup$
– Decaf-Math
Dec 14 '18 at 17:36
$begingroup$
This may be useful.
$endgroup$
– Decaf-Math
Dec 14 '18 at 17:36
$begingroup$
@Decaf-Math this link 1) isn't useful because it cannot give the method to follow 2) I have tried it with a failure to give an answer
$endgroup$
– Jean Marie
Dec 14 '18 at 17:56
$begingroup$
@Decaf-Math this link 1) isn't useful because it cannot give the method to follow 2) I have tried it with a failure to give an answer
$endgroup$
– Jean Marie
Dec 14 '18 at 17:56
2
2
$begingroup$
@Gady-ManuelAlaoui Normally I would respect the hold and not comment, but this question is so tricky that I feel it is unreasonable to expect you to "show your work". I will give a series of comments that provide an outline of the solution.
$endgroup$
– user2661923
Dec 14 '18 at 20:36
$begingroup$
@Gady-ManuelAlaoui Normally I would respect the hold and not comment, but this question is so tricky that I feel it is unreasonable to expect you to "show your work". I will give a series of comments that provide an outline of the solution.
$endgroup$
– user2661923
Dec 14 '18 at 20:36
1
1
$begingroup$
Using integration by parts, $I = ln(u)cos(u) - int [(cos u)/u] ;du.$ Re one of my previous comments, this completes the problem, at least as far as $int ln[text{arccos}(x)] ;dx$ is concerned.
$endgroup$
– user2661923
Dec 14 '18 at 20:50
$begingroup$
Using integration by parts, $I = ln(u)cos(u) - int [(cos u)/u] ;du.$ Re one of my previous comments, this completes the problem, at least as far as $int ln[text{arccos}(x)] ;dx$ is concerned.
$endgroup$
– user2661923
Dec 14 '18 at 20:50
|
show 4 more comments
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1
$begingroup$
Use proofwiki.org/wiki/Difference_of_Logarithms and mathworld.wolfram.com/IntegrationbyParts.html
$endgroup$
– lab bhattacharjee
Dec 14 '18 at 17:24
$begingroup$
This may be useful.
$endgroup$
– Decaf-Math
Dec 14 '18 at 17:36
$begingroup$
@Decaf-Math this link 1) isn't useful because it cannot give the method to follow 2) I have tried it with a failure to give an answer
$endgroup$
– Jean Marie
Dec 14 '18 at 17:56
2
$begingroup$
@Gady-ManuelAlaoui Normally I would respect the hold and not comment, but this question is so tricky that I feel it is unreasonable to expect you to "show your work". I will give a series of comments that provide an outline of the solution.
$endgroup$
– user2661923
Dec 14 '18 at 20:36
1
$begingroup$
Using integration by parts, $I = ln(u)cos(u) - int [(cos u)/u] ;du.$ Re one of my previous comments, this completes the problem, at least as far as $int ln[text{arccos}(x)] ;dx$ is concerned.
$endgroup$
– user2661923
Dec 14 '18 at 20:50