What is the name of $C(A)/A$












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Given a topological space $A$, $C(A)$ is the cone of $A$. The space $C(A)/A$ is clearly homotopic to the suspension. My question is if it has a widely known name?










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  • 1




    $begingroup$
    Isn't this homeomorphic to the suspension? I assume you mean $C(A)/(Atimes{0})$.
    $endgroup$
    – Stefan Hamcke
    Nov 8 '13 at 23:24












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    double cone or suspension (don't confuse it with the reduced suspension $A wedge mathbb{S}^1$).
    $endgroup$
    – user40276
    Nov 8 '13 at 23:32










  • $begingroup$
    @StefanH I asked a stupid question. What in my mind is asking the name for the simplicial set $Delta^0 star Acup_{A} Delta^0$ the pushout for the canonical maps $Asubset Delta^0 star A$ and $Ato Delta^0$ for a simplicial set $A$, where star is the simplicial join (a cone).
    $endgroup$
    – Ma Ming
    Nov 9 '13 at 0:33


















1












$begingroup$


Given a topological space $A$, $C(A)$ is the cone of $A$. The space $C(A)/A$ is clearly homotopic to the suspension. My question is if it has a widely known name?










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Isn't this homeomorphic to the suspension? I assume you mean $C(A)/(Atimes{0})$.
    $endgroup$
    – Stefan Hamcke
    Nov 8 '13 at 23:24












  • $begingroup$
    double cone or suspension (don't confuse it with the reduced suspension $A wedge mathbb{S}^1$).
    $endgroup$
    – user40276
    Nov 8 '13 at 23:32










  • $begingroup$
    @StefanH I asked a stupid question. What in my mind is asking the name for the simplicial set $Delta^0 star Acup_{A} Delta^0$ the pushout for the canonical maps $Asubset Delta^0 star A$ and $Ato Delta^0$ for a simplicial set $A$, where star is the simplicial join (a cone).
    $endgroup$
    – Ma Ming
    Nov 9 '13 at 0:33
















1












1








1





$begingroup$


Given a topological space $A$, $C(A)$ is the cone of $A$. The space $C(A)/A$ is clearly homotopic to the suspension. My question is if it has a widely known name?










share|cite|improve this question











$endgroup$




Given a topological space $A$, $C(A)$ is the cone of $A$. The space $C(A)/A$ is clearly homotopic to the suspension. My question is if it has a widely known name?







general-topology algebraic-topology






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share|cite|improve this question













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share|cite|improve this question








edited Nov 8 '13 at 23:27









Stefan Hamcke

21.8k42880




21.8k42880










asked Nov 8 '13 at 23:23









Ma MingMa Ming

6,5661331




6,5661331








  • 1




    $begingroup$
    Isn't this homeomorphic to the suspension? I assume you mean $C(A)/(Atimes{0})$.
    $endgroup$
    – Stefan Hamcke
    Nov 8 '13 at 23:24












  • $begingroup$
    double cone or suspension (don't confuse it with the reduced suspension $A wedge mathbb{S}^1$).
    $endgroup$
    – user40276
    Nov 8 '13 at 23:32










  • $begingroup$
    @StefanH I asked a stupid question. What in my mind is asking the name for the simplicial set $Delta^0 star Acup_{A} Delta^0$ the pushout for the canonical maps $Asubset Delta^0 star A$ and $Ato Delta^0$ for a simplicial set $A$, where star is the simplicial join (a cone).
    $endgroup$
    – Ma Ming
    Nov 9 '13 at 0:33
















  • 1




    $begingroup$
    Isn't this homeomorphic to the suspension? I assume you mean $C(A)/(Atimes{0})$.
    $endgroup$
    – Stefan Hamcke
    Nov 8 '13 at 23:24












  • $begingroup$
    double cone or suspension (don't confuse it with the reduced suspension $A wedge mathbb{S}^1$).
    $endgroup$
    – user40276
    Nov 8 '13 at 23:32










  • $begingroup$
    @StefanH I asked a stupid question. What in my mind is asking the name for the simplicial set $Delta^0 star Acup_{A} Delta^0$ the pushout for the canonical maps $Asubset Delta^0 star A$ and $Ato Delta^0$ for a simplicial set $A$, where star is the simplicial join (a cone).
    $endgroup$
    – Ma Ming
    Nov 9 '13 at 0:33










1




1




$begingroup$
Isn't this homeomorphic to the suspension? I assume you mean $C(A)/(Atimes{0})$.
$endgroup$
– Stefan Hamcke
Nov 8 '13 at 23:24






$begingroup$
Isn't this homeomorphic to the suspension? I assume you mean $C(A)/(Atimes{0})$.
$endgroup$
– Stefan Hamcke
Nov 8 '13 at 23:24














$begingroup$
double cone or suspension (don't confuse it with the reduced suspension $A wedge mathbb{S}^1$).
$endgroup$
– user40276
Nov 8 '13 at 23:32




$begingroup$
double cone or suspension (don't confuse it with the reduced suspension $A wedge mathbb{S}^1$).
$endgroup$
– user40276
Nov 8 '13 at 23:32












$begingroup$
@StefanH I asked a stupid question. What in my mind is asking the name for the simplicial set $Delta^0 star Acup_{A} Delta^0$ the pushout for the canonical maps $Asubset Delta^0 star A$ and $Ato Delta^0$ for a simplicial set $A$, where star is the simplicial join (a cone).
$endgroup$
– Ma Ming
Nov 9 '13 at 0:33






$begingroup$
@StefanH I asked a stupid question. What in my mind is asking the name for the simplicial set $Delta^0 star Acup_{A} Delta^0$ the pushout for the canonical maps $Asubset Delta^0 star A$ and $Ato Delta^0$ for a simplicial set $A$, where star is the simplicial join (a cone).
$endgroup$
– Ma Ming
Nov 9 '13 at 0:33












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$begingroup$

This community wiki solution is intended to clear the question from the unanswered queue.



Taken from the comments:



$C(A)/A$ is homeomorphic to the suspension of $A$. Therefore it does not need a separate name.






share|cite|improve this answer











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    $begingroup$

    This community wiki solution is intended to clear the question from the unanswered queue.



    Taken from the comments:



    $C(A)/A$ is homeomorphic to the suspension of $A$. Therefore it does not need a separate name.






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      This community wiki solution is intended to clear the question from the unanswered queue.



      Taken from the comments:



      $C(A)/A$ is homeomorphic to the suspension of $A$. Therefore it does not need a separate name.






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        This community wiki solution is intended to clear the question from the unanswered queue.



        Taken from the comments:



        $C(A)/A$ is homeomorphic to the suspension of $A$. Therefore it does not need a separate name.






        share|cite|improve this answer











        $endgroup$



        This community wiki solution is intended to clear the question from the unanswered queue.



        Taken from the comments:



        $C(A)/A$ is homeomorphic to the suspension of $A$. Therefore it does not need a separate name.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        answered Dec 29 '18 at 16:27


























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        Paul Frost































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