System of distinct representative professors and students problem












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So I was doing exercises from a Combinatorics textbook. I ran into this problem.



Suppose we have $n$ students, $s_1,s_2,dots,s_n,$ and $n$ professors,
$p_1,p_2,dots,p_n$. For each student $s_i$ we define a set of his/her favorite professors, $S_i$. Every student has at most $f$ favorite professors (where $fgeq 3$), while each professor $p_j$ appears in at least $f$ sets $S_{j_1},S_{j_2},dots,S_{j_f}$.



For a given value of $f$, let $pi_i (f)$ be the number of appearances of professor $p_i$ on the students' lists, and $sigma_j (f)= |S_j|$.



$1.$ What is $operatorname{max}{pi_i(f)| 1leq ileq n}$ and
$operatorname{min}{sigma_j(f)| 1leq jleq n}$ for a fixed value of $f$? Note that you are not looking the max or min over the whole range of values of $f$, but rather for any given value, and the range is all values of $i$. So, your answer is a function of $f$



$2.$ Every student needs three letters of recommendation. Can they select their favorite professors for the letters so that no professor writes more than three letters? Prove your claim or show a counter-example.



How would you solve this? I recognize that this is a system of distinct representatives kind of problem. But somehow I can't think of a way to find a solution. Please help!










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    1












    $begingroup$


    So I was doing exercises from a Combinatorics textbook. I ran into this problem.



    Suppose we have $n$ students, $s_1,s_2,dots,s_n,$ and $n$ professors,
    $p_1,p_2,dots,p_n$. For each student $s_i$ we define a set of his/her favorite professors, $S_i$. Every student has at most $f$ favorite professors (where $fgeq 3$), while each professor $p_j$ appears in at least $f$ sets $S_{j_1},S_{j_2},dots,S_{j_f}$.



    For a given value of $f$, let $pi_i (f)$ be the number of appearances of professor $p_i$ on the students' lists, and $sigma_j (f)= |S_j|$.



    $1.$ What is $operatorname{max}{pi_i(f)| 1leq ileq n}$ and
    $operatorname{min}{sigma_j(f)| 1leq jleq n}$ for a fixed value of $f$? Note that you are not looking the max or min over the whole range of values of $f$, but rather for any given value, and the range is all values of $i$. So, your answer is a function of $f$



    $2.$ Every student needs three letters of recommendation. Can they select their favorite professors for the letters so that no professor writes more than three letters? Prove your claim or show a counter-example.



    How would you solve this? I recognize that this is a system of distinct representatives kind of problem. But somehow I can't think of a way to find a solution. Please help!










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      So I was doing exercises from a Combinatorics textbook. I ran into this problem.



      Suppose we have $n$ students, $s_1,s_2,dots,s_n,$ and $n$ professors,
      $p_1,p_2,dots,p_n$. For each student $s_i$ we define a set of his/her favorite professors, $S_i$. Every student has at most $f$ favorite professors (where $fgeq 3$), while each professor $p_j$ appears in at least $f$ sets $S_{j_1},S_{j_2},dots,S_{j_f}$.



      For a given value of $f$, let $pi_i (f)$ be the number of appearances of professor $p_i$ on the students' lists, and $sigma_j (f)= |S_j|$.



      $1.$ What is $operatorname{max}{pi_i(f)| 1leq ileq n}$ and
      $operatorname{min}{sigma_j(f)| 1leq jleq n}$ for a fixed value of $f$? Note that you are not looking the max or min over the whole range of values of $f$, but rather for any given value, and the range is all values of $i$. So, your answer is a function of $f$



      $2.$ Every student needs three letters of recommendation. Can they select their favorite professors for the letters so that no professor writes more than three letters? Prove your claim or show a counter-example.



      How would you solve this? I recognize that this is a system of distinct representatives kind of problem. But somehow I can't think of a way to find a solution. Please help!










      share|cite|improve this question









      $endgroup$




      So I was doing exercises from a Combinatorics textbook. I ran into this problem.



      Suppose we have $n$ students, $s_1,s_2,dots,s_n,$ and $n$ professors,
      $p_1,p_2,dots,p_n$. For each student $s_i$ we define a set of his/her favorite professors, $S_i$. Every student has at most $f$ favorite professors (where $fgeq 3$), while each professor $p_j$ appears in at least $f$ sets $S_{j_1},S_{j_2},dots,S_{j_f}$.



      For a given value of $f$, let $pi_i (f)$ be the number of appearances of professor $p_i$ on the students' lists, and $sigma_j (f)= |S_j|$.



      $1.$ What is $operatorname{max}{pi_i(f)| 1leq ileq n}$ and
      $operatorname{min}{sigma_j(f)| 1leq jleq n}$ for a fixed value of $f$? Note that you are not looking the max or min over the whole range of values of $f$, but rather for any given value, and the range is all values of $i$. So, your answer is a function of $f$



      $2.$ Every student needs three letters of recommendation. Can they select their favorite professors for the letters so that no professor writes more than three letters? Prove your claim or show a counter-example.



      How would you solve this? I recognize that this is a system of distinct representatives kind of problem. But somehow I can't think of a way to find a solution. Please help!







      combinatorics






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      asked Dec 3 '18 at 17:28









      DummKorfDummKorf

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          $begingroup$

          Let $f(S_{j},p_{i})=begin{cases} 1 & S_{j} text{ likes }p_{i}\ 0 & text{otherwise}end{cases}$.$sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})leq nf$ as every student has at most $f$ favorite professors and $sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})geq nf$ as each professor is the favourite of at least $f$ students. Therefore, each student has exactly $f$ favorite professors and each professor is the favourite of exactly $f$ students.
          Hence, $pi_i (f)=sigma_j (f)= f$.
          The answer to the second part is in the affirmative.






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            $begingroup$

            Let $f(S_{j},p_{i})=begin{cases} 1 & S_{j} text{ likes }p_{i}\ 0 & text{otherwise}end{cases}$.$sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})leq nf$ as every student has at most $f$ favorite professors and $sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})geq nf$ as each professor is the favourite of at least $f$ students. Therefore, each student has exactly $f$ favorite professors and each professor is the favourite of exactly $f$ students.
            Hence, $pi_i (f)=sigma_j (f)= f$.
            The answer to the second part is in the affirmative.






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              Let $f(S_{j},p_{i})=begin{cases} 1 & S_{j} text{ likes }p_{i}\ 0 & text{otherwise}end{cases}$.$sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})leq nf$ as every student has at most $f$ favorite professors and $sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})geq nf$ as each professor is the favourite of at least $f$ students. Therefore, each student has exactly $f$ favorite professors and each professor is the favourite of exactly $f$ students.
              Hence, $pi_i (f)=sigma_j (f)= f$.
              The answer to the second part is in the affirmative.






              share|cite|improve this answer









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                $begingroup$

                Let $f(S_{j},p_{i})=begin{cases} 1 & S_{j} text{ likes }p_{i}\ 0 & text{otherwise}end{cases}$.$sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})leq nf$ as every student has at most $f$ favorite professors and $sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})geq nf$ as each professor is the favourite of at least $f$ students. Therefore, each student has exactly $f$ favorite professors and each professor is the favourite of exactly $f$ students.
                Hence, $pi_i (f)=sigma_j (f)= f$.
                The answer to the second part is in the affirmative.






                share|cite|improve this answer









                $endgroup$



                Let $f(S_{j},p_{i})=begin{cases} 1 & S_{j} text{ likes }p_{i}\ 0 & text{otherwise}end{cases}$.$sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})leq nf$ as every student has at most $f$ favorite professors and $sumlimits_{j=1}^nsum limits_{i=1}^nf(S_{j},p_{i})geq nf$ as each professor is the favourite of at least $f$ students. Therefore, each student has exactly $f$ favorite professors and each professor is the favourite of exactly $f$ students.
                Hence, $pi_i (f)=sigma_j (f)= f$.
                The answer to the second part is in the affirmative.







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                answered Dec 3 '18 at 18:14









                Anubhab GhosalAnubhab Ghosal

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